336=5x^2

Solution for 336=5x^2 equation:

336=5x^2

We move all terms to the left:

336-(5x^2)=0

a = -5; b = 0; c = +336;
Δ = b2-4ac
Δ = 02-4·(-5)·336
Δ = 6720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6720}=\sqrt{64*105}=\sqrt{64}*\sqrt{105}=8\sqrt{105}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{105}}{2*-5}=\frac{0-8\sqrt{105}}{-10}
=-\frac{8\sqrt{105}}{-10}
=-\frac{4\sqrt{105}}{-5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{105}}{2*-5}=\frac{0+8\sqrt{105}}{-10}
=\frac{8\sqrt{105}}{-10}
=\frac{4\sqrt{105}}{-5}
$